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16n^2-10n-5-(6n)=0
We add all the numbers together, and all the variables
16n^2-16n-5=0
a = 16; b = -16; c = -5;
Δ = b2-4ac
Δ = -162-4·16·(-5)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*16}=\frac{-8}{32} =-1/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*16}=\frac{40}{32} =1+1/4 $
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